q^2-17q+16=0

Solution for q^2-17q+16=0 equation:

Simplifying
q2 + -17q + 16 = 0

Reorder the terms:
16 + -17q + q2 = 0

Solving
16 + -17q + q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(1 + -1q)(16 + -1q) = 0

Subproblem 1
Set the factor '(1 + -1q)' equal to zero and attempt to solve:

Simplifying
1 + -1q = 0

Solving
1 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1q = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1q = 0 + -1
-1q = 0 + -1

Combine like terms: 0 + -1 = -1
-1q = -1

Divide each side by '-1'.
q = 1

Simplifying
q = 1
Subproblem 2
Set the factor '(16 + -1q)' equal to zero and attempt to solve:

Simplifying
16 + -1q = 0

Solving
16 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1q = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1q = 0 + -16
-1q = 0 + -16

Combine like terms: 0 + -16 = -16
-1q = -16

Divide each side by '-1'.
q = 16

Simplifying
q = 16
Solution
q = {1, 16}